抗弯验算:Mmax=max[qlb2/8,qa12/2]=max[1.595×12/8,1.595×0.152/2]=0.199kN·m
σ=γ0Mmax/W=1×0.199×106/5080=39.245N/mm2≤[f]=205N/mm2
满足要求!
挠度验算:νmax=max[5q'lb4/(384EI),q'a14/(8EI)]=max[5×1.188×10004/(384×206000×121900),1.188×1504/(8×206000×121900)]=0.616mm
νmax=0.616mm≤[ν]=min[lb/150,10]=min[1000/150,10]=6.667mm
满足要求!
支座反力计算:承载能力极限状态
Rmax=q(lb+a1)2/(2lb)=1.595×(1+0.15)2/(2×1)=1.055kN
正常使用极限状态
Rmax'=q'(lb+a1)2/(2lb)=1.188×(1+0.15)2/(2×1)=0.786kN
纵向水平杆验算:承载能力极限状态
由上节可知F1=Rmax=1.055kN
q=1.3×0.038=0.05kN/m
正常使用极限状态
由上节可知F1'=Rmax'=0.786kN